#include <stdio.h>
#include <stdlib.h>

/**
 * Prompt ("num? ") for an integer number from the user, then get the number
 * from the user. If the number read is evenly divided by 3 print "Foo", if
 * it's evenly divided by 5 print "Bar" and if it's evenly divided by both 3
 * and 5 print "FooBar". If it is not evenly divided by either, just print
 * the number itself.  If scanf fails to read read the number (return value
 * is not 1), then print "Not a number".
 * Hint: To determine if a number is divisible by another, use the mod (%)
 * operator.  A number is evenly divisible by another if the result of the
 * mod operation is 0 (i.e. x % 7 == 0 when x is divisible by 7.)
 * 
 * Example input/outputs:
 * > ./h3
 * num? 15
 * FooBar
 * > ./h3
 * num? 5
 * Bar
 * > ./h3
 * num? 43
 * 43
 */

int main(void)
{
  int num;

  printf("num? ");
  if (scanf("%d", &num) != 1) printf("Not a number");
  else if (num % 3 == 0 && num % 5 == 0) printf("FooBar\n");
  else if (num % 3 == 0) printf("Foo\n");
  else if (num % 5 == 0) printf("Bar\n");
  else printf("%d\n", num);

  return 0;
}